Solution
since , $$cosecA=secB$$ if $$A+B$$ = $$90^\circ$$
So, $$4\theta+(60^\circ-2\theta)$$ = $$90^\circ$$
$$\Rightarrow$$ $$2\theta=30^\circ$$
$$ \Rightarrow$$ $$\theta=15^\circ$$
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