Question 75

If $$\cosec 4\theta = \sec (60^\circ - 2\theta),  then  \theta $$ is equal to:

Solution

since ,  $$cosecA=secB$$ if $$A+B$$ = $$90^\circ$$

 So, $$4\theta+(60^\circ-2\theta)$$ = $$90^\circ$$

    $$\Rightarrow$$ $$2\theta=30^\circ$$

     $$ \Rightarrow$$ $$\theta=15^\circ$$


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