Question 75

If $$\cosec 4\theta = \sec (60^\circ - 2\theta), then \theta $$ is equal to:

Solution

since , $$cosecA=secB$$ if $$A+B$$ = $$90^\circ$$

So, $$4\theta+(60^\circ-2\theta)$$ = $$90^\circ$$

$$\Rightarrow$$ $$2\theta=30^\circ$$

$$ \Rightarrow$$ $$\theta=15^\circ$$

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