In these questions, two equations numbered I and H are given. You have to solve both the equations and mark the appropriate option.
Give answer :
a: If relationship between x and y cannot be established
b: If x < y
c: If x > y
d: If x ≤ y
e: If x ≥ y
I. $$25x^{2} + 20x + 3 =0$$
II. $$4y^{2} + 11y+ 6 =0$$
Root of quadratic equation (ax$$^2$$ + bx + c =0) = $$\frac{-b \pm \sqrt{(b^2 -4ac)}}{2a}$$
For equation I : a=25 , b =20 and c= 3
On solving the quadratic equation I we get x = (-30/50) or (-10/50)
For equation II : a=4 , b =11 and c= 6
On solving the quadratic equation I we get y = (-6/8) or (-16/8)
It is clear that x>y
Option C is correct answer.
Create a FREE account and get:
Quick, Easy and Effective Revision
By proceeding you agree to create your account
Free CAT Formulae PDF will be sent to your email address soon !!!
