The value of $$\sqrt{\tan^2 60^\circ + \sin 90^\circ} - 2 \tan 45^\circ$$ is:
$$\sqrt{\tan^2 60^\circ + \sin 90^\circ} - 2 \tan 45^\circ$$
On putting the values,
$$\sqrt{(\sqrt3)^2 + 1} - 2 \times 1$$
$$\sqrt{(4} - 2 $$Â
= 2 - 2 = 0
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