Question 74

The value of $$\sqrt{\tan^2 60^\circ + \sin 90^\circ} - 2 \tan 45^\circ$$ is:

Solution

$$\sqrt{\tan^2 60^\circ + \sin 90^\circ} - 2 \tan 45^\circ$$

On putting the values,

$$\sqrt{(\sqrt3)^2 + 1} - 2 \times 1$$

$$\sqrt{(4} - 2 $$ 

= 2 - 2 = 0


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App