The area of isosceles trapezium is 176 $$cm^{2}$$ and the height h is$$ \frac{2}{11}$$ th of the sum of its parallel sides if the ratio of the length of the parallel sides is 4:7, then the length of a diagonal {in cm) is
Area =12(sum of parallel sides)× distance between them
12(7x+4x)×2x=176
11x2=176x216
x=4
AB=7×4=28cm
CD=4×4=16cm
CM=2×4=8cm
AM=AN+NM
AN+16
6+16=22
(AN=BM > =12/2=6)
AC^2=CM^2+AM^2
AC^2=8^2+22^2
AC= √ (64+484)------- √(548)...= 2√(137)
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