A friend is spotted by Lala at a distance of 200 m. When Lala starts to approach him, the friend also starts moving in the same direction as Lala. If the speed of his friend is 15 kmph, and that of Lala is 20 kmph, then how far will the friend have to walk before Lala meets him ?
Solution
Since both move in the same direction:
Relative Speed = 20 - 15 = 5 Km/hr
Convert to m/s: $$5\times\dfrac{1000}{3600}=\dfrac{25}{18}$$ m/sec
Time taken to catch up = $$\dfrac{200}{\dfrac{25}{18}}=200\times\dfrac{18}{25}=144\ $$ seconds
Friend’s speed = 15 km/h
So the distance walked by that friend = $$15\times\dfrac{1000}{3600}=\dfrac{25}{6}$$ m/sec
Distance = $$\dfrac{25}{6}\times144=600\ m$$
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