Question 73

Two positive numbers differ by 2001, When the larger number is divided by the smaller number, the quotient is 9 and the remainder is 41. The sum of the digits ofthe larger number is:

Solution

Let the 1 number be x.
Larger number = x + 2001
Quotient = x,
Dividend = x + 2001
$$Quotient \times divisor + remainder = dividend$$
$$9x + 41 = x + 2001$$
8x = 1960
x = 245
Larger number = 2001 + 245 = 2246
Sm of the larger number = 2 + 2 + 4 + 6 = 14

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SSC CGL Tier-2 13th September 2019 Maths

Two positive numbers differ by 2001, When the larger number is divided by the smaller number, the quotient is 9 and the remainder is 41. The sum of the digits ofthe larger number is:

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