Question 73

The base and altitude of an isosceles triangle are 10 cm and 12 cm respectively. Then the length of each equal side is:

Solution

In the isosceles triangle, the altitude bisects the base as shown above.

Let the length of equal sides = a

From $$\triangle$$ABD,

BD$$^2$$ + AD$$^2$$ = AB$$^2$$

$$\Rightarrow$$ 5$$^2$$ + 12$$^2$$ = a$$^2$$

$$\Rightarrow$$ 25 + 144 = a$$^2$$

$$\Rightarrow$$ a$$^2$$ = 169

$$\Rightarrow$$ a = 13 cm

$$\therefore\ $$Length of each equal side = 13 cm

Hence, the correct answer is Option A

Create a FREE account and get:

Free SSC Study Material - 18000 Questions
230+ SSC previous papers with solutions PDF
100+ SSC Online Tests for Free

CAT Quant Questions | CAT Quantitative Ability

CAT Profit And Loss Questions CAT Arithmetic Questions CAT Coordinate Geometry Questions CAT Quadratic Equations Questions CAT Probability, Combinatorics Questions

CAT DILR Questions | LRDI Questions For CAT

CAT Selection With Condition Questions CAT DI Miscellaneous Questions CAT Coins and Weights Questions CAT Venn Diagrams Questions CAT Charts Questions

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Grammar and Sentence Correction Questions CAT Para Summary Questions CAT Verbal Ability Questions CAT Reading Comprehension Questions CAT Miscellaneous Questions

Follow us on

Boost your Prep!

Download App