When the price of an item was reduced by 20%, then its sales increased by x%. If there is an increase of 60% in the receipt of the revenue, then the value of x is:

Let the price of one article =1 Rs.

After the reduction in the price, the new price of the article $$=\times{1\times 80}{100}=0.8$$Rs.

Let initial consumption of the good =100

New consumption of the good=100+x,

After Increase in the revenue, new revenue =160% of initial revenue $$=\dfrac{160\times 100}{100}$$

Hence, $$(100+x)\times 0.8=\dfrac{160\times 100}{100}$$

$$\Rightarrow 80+0.8x=160$$

$$\Rightarrow 0.8x=160-80=80$$

$$\Rightarrow x=\dfrac{80}{0.8}=100$$

Hence, increase in the sales is $$100\%$$