Question 72

The value of $$\frac{5+2 of 3 \div3 of 2\times3}{9+72\div3-2\times(3-2)-3}$$ is $$\frac{a}{b}$$, where a and b are prime numbers. The value of $$(b - a)$$ is:

Solution

$$\frac{a}{b}=\frac{5+2\ of\ 3\div3\ of\ 2\times3}{9+72\div3-2\times(3-2)-3}$$

$$\frac{a}{b}=\frac{5+6\div6\times3}{9+24-2\times1-3}$$

$$\frac{a}{b}=\frac{5+1\times3}{33-2-3}$$

$$\frac{a}{b}=\frac{5+3}{33-5}$$

$$\frac{a}{b}=\frac{8}{28}$$

$$\frac{a}{b}=\frac{2}{7}$$

value of $$(b - a)$$ = (7-2)

= 5

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