Question 72
In a trapezium ABCD, DC $$\parallel$$ AB , AB = 12 cm and DC = 7.2 cm. What is the length of the line segment joining the midpoints of its diagonals?
Solution
By the property,
EF = $$\frac{AB - CD}{2}$$
= $$\frac{12 - 7.2}{2} = \frac{4.8}{2} = 2.4 cm$$
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