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If cube root of unity are $$1, w, w^2$$ then the roots of equation $$(x - 1)^3 + 8 = 0$$ are
$$-1, -1+2w, -1-2w^2$$
$$-1, -1, -1$$
$$-1, 1 - 2w, 1 - 2w^2$$
$$-1, -1 + 2w, 1 + 2w^2$$
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