If cube root of unity are $$1, w, w^2$$ then the roots of equation $$(x - 1)^3 + 8 = 0$$ are

A

$$-1, -1+2w, -1-2w^2$$

B

$$-1, -1, -1$$

C

$$-1, 1 - 2w, 1 - 2w^2$$

D

$$-1, -1 + 2w, 1 + 2w^2$$