A is 25% more than B while B is 20% less than C and C is 10% more than D. Which of the following is not true?

Given, 

A is 25% more than B while B is 20% less than C and C is 10% more than D

Let the D = 100 

Then, C = $$100\times\ \frac{110}{100}=110$$

$$\therefore B=\ 110\times\ \frac{80}{100}=88$$

$$\therefore A=\ 88\times\ \frac{125}{100}=110$$

Lets check option wise : 

Option A : 

B is 22% less than A : 

i.e; Required % = $$\frac{110-88}{110}\times\ 100\ =\ 20\%$$

So, Option A is not true. 

Option B : 

A is 10% more than D

i.e; = $$\frac{110-100}{100}\times\ 100\ =\ 10\%$$

So, Option B is true

Option C : 

B is 12 % less than D :

$$\frac{100-88}{100}\times\ 100\ =\ 12\%$$

So, Option C is true

Option D : 

A = C

A = 110 , C = 110

So, Option D is true, 

Hence, Option A is not true. that is correct answer.