Solution
$$\sin60^{\circ}\cos30^{\circ}-\cos60^{\circ}\sin30^{\circ}=\frac{\sqrt{3}}{2}\times\frac{\sqrt{3}}{2}-\frac{1}{2}\times\frac{1}{2}$$
$$=\frac{3}{4}-\frac{1}{4}$$
$$=\frac{2}{4}$$
$$=\frac{1}{2}$$
Hence, the correct answer is Option B
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