A train, 700 m long crosses a pole in 35 seconds. How much time does it take to cross a platform of length 740 m?
Let the speed of the train be x $$\frac{m}{s}$$
From the formula we have,speed = $$\frac{distance}{time}$$
So, x = $$\frac{700}{35}$$ = 20 $$\frac{m}{s}$$
Time taken by the train to cross a platform of 740 m will be =$$\frac{total\ dis\tan ce}{speed}$$
$$\Rightarrow$$ $$\frac{(700+740)}{20}$$ = 72 sec or 1 min 12 sec.
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