Question 71

A student got 24% marks in an exam and he failed by 56 marks. If he got 60% marks, then his marks are 70 more than the minimum passing marks. What is the maximum marks for the exam?

Solution

Let maximum marks in the exam = $$100x$$ and minimum passing marks = $$y$$

=> Minimum passing marks = $$y=24x+56$$ --------------(i)

Also, $$y=60x-70$$ ----------------(ii)

Comparing both the equations, we get :

=> $$24x+56=60x-70$$

=> $$36x=70+56=126$$

=> $$x=\frac{126}{36}=3.5$$

$$\therefore$$ Maximum marks = $$100\times3.5=350$$

=> Ans - (A)

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