What is the average of all the natural numbers from 49 to 125?
let no. of terms be n
Sum of no. = $$\frac{no.\ of\ term}{2}\times(first\ term+last\ term)$$
          = $$\frac{n}{2} \times(49+125)$$
$$Avg=\frac{sum\ of\ no.}{no.\ of\ term}$$
    $$\frac{\frac{n}{2} \times(49+125)}{n}$$
    = $$\frac{49 +125}{2}$$
   =$$\frac{49 +125}{2}$$
   =87
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