Question 70

What is the average of all the natural numbers from 49 to 125?

Solution

let no. of terms be n

Sum of no. = $$\frac{no.\ of\ term}{2}\times(first\ term+last\ term)$$

= $$\frac{n}{2} \times(49+125)$$

$$Avg=\frac{sum\ of\ no.}{no.\ of\ term}$$

$$\frac{\frac{n}{2} \times(49+125)}{n}$$

= $$\frac{49 +125}{2}$$

=$$\frac{49 +125}{2}$$

=87

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