Solution
let no. of terms be n
Sum of no. = $$\frac{no.\ of\ term}{2}\times(first\ term+last\ term)$$
= $$\frac{n}{2} \times(49+125)$$
$$Avg=\frac{sum\ of\ no.}{no.\ of\ term}$$
$$\frac{\frac{n}{2} \times(49+125)}{n}$$
= $$\frac{49 +125}{2}$$
=$$\frac{49 +125}{2}$$
=87
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