The radius of a sphereis increased by 140%. By what percent will its volume increase?
Volume of sphere = $$\frac{4}{3}\pi\ r^3$$
Now when r is increased by 140% we get new r = 2.4r
so volume becomes =$$\frac{4}{3}\pi\ \left(2.4r\right)^3$$
Now percentage increase =Â $$\frac{\left(\frac{4}{3}\pi\ \left(2.4r\right)^3\right)-\frac{4}{3}\pi\ r^3}{\frac{4}{3}\pi\ r^3}$$
we get 1282.4%
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