Question 70

Diameter of a roller is 2.4 m and it is 1.68 m long. If it takes 1000 complete revolutions once over to level a field, the area of the field is

Solution

Radius of roller = 1.2 m and height = 1.68 m

Area covered in 1 revolution = $$2 \pi r h$$

= $$2 \times \frac{22}{7} \times 1.2 \times 1.68$$

= $$44 \times 1.2 \times 0.24 = 12.672 m^2$$

$$\therefore$$ Area of the field = Area covered in 1000 revolutions

= $$12.672 \times 1000 = 12672 m^2$$

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