Question 70

A certain sum is lent at x% p.a. simple interest for $$\frac{x}{3}$$ years. The simple interest on the sum is equal to one-third of the sum. The value of x is:

Solution

P = principal amount

R = rate of interest

T = time

The simple interest on the sum is equal to one-third of the sum.

Let's assume the initial sum is 'y'.

simple interest = $$\frac{y}{3}$$

simple interest = $$\frac{P\times\ R\times\ T}{100}$$

$$\frac{y}{3}=\frac{y\times\ x\times\ x}{100\times\ 3}$$

$$\frac{1}{3}=\frac{\ x\times\ x}{100\times\ 3}$$

$$1=\frac{\ x\times\ x}{100}$$

$$x^2=10^2$$

value of x = 10


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