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Question 70
220 articles droped in a water tank which is 52 m long and 47 m broad. If the average displacement of water by an article is 4.5 m$$^3$$ , then approximate rise in the water level will be:
Solution
Displacement of water by 220 articles = $$220\times4.5 = 990 m^3$$
Let the approximate rise in water be h m
$$990 = 52 \times 47 \times h$$
=> h = 990/2444 = 0.405 m = 40.5 cm
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