7 to the power 13 + 6 to the power 12 + 1 to the power 11 + 4 to the power 7 how find out whether this expression is even or odd, how to solve this equation

I hope the question is this $$((((7^{13}+6)^{12}+1)^{11}+4)^{7})$$ . If it is different please let me know.
$$7^{13}$$ is odd if we add 6 to it, it will still be odd. $$odd^{12}$$ is odd, if we add 1 to it it will become even. Now $$(even)^{11}$$ will be even and adding 4 to it will give even only. $$(Even)^{7}$$ is even so the final result is even. I hope it helps.
Thanks

as you have put the bracket in the equation their was no bracket in the question in my test paper but the ans is even only thank you