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Rajesh, a courier delivery agent, starts at point A and makes a delivery each at points B, C and D, in that order. He travels in a straight line between any two consecutive points. The following are known: (i) AB and CD intersect at a right angle at E, and (ii) BC, CE and ED are respectively 1.3 km, 0.5 km and 2.5 km long. If AD is parallel to BC, then what is the total distance (in km) that Rajesh covers in travelling from A to D?
Based on the information, the following figure can be obtained.
Given, CE=0.5, BC = 1.3 and ED=2.5
Triangle CEB is a right-angled triangle => EB = 1.2
$$\triangle\ $$ ECB is similar to $$\triangle\ $$ EDA
EB/EC = AE/ED => AE = 6
Hence total distance travelled = AB + BC + CD = 7.2 + 1.3 + 3 = 11.5km
Video Solution
Your Doubts
I did by this method ,my answer is coming different from sirs answer can anyone answer this?
everything is correct but my diagram is somewhat different
Hi Anupam Das,
According to the given condition in the question, the diagram will be as shown above. Please let me know if you have any other doubts regarding the same,
Regards
Sir what is the problem in this diagram .
But question is not solving by this diagram
with this diagram the answer is coming but not given in the options
