Question 69

What is the value of $$sin(\frac{-\pi}{3})+cos(\frac{-\pi}{6})$$ ?

Solution

Expression : $$sin(\frac{-\pi}{3})+cos(\frac{-\pi}{6})$$

$$\because sin(-\theta)=-sin\theta$$ and $$cos(-\theta)=cos\theta$$

= $$-sin(\frac{\pi}{3})+cos(\frac{\pi}{6})$$

= $$-\frac{\sqrt3}{2}+\frac{\sqrt3}{2}$$

= $$0$$

=> Ans - (A)

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