The sides of a rhombus ABCD are parallel to the lines, $$x - y + 2 = 0$$ and $$7x - y + 3 = 0$$. If the diagonals of the rhombus intersect at P(1, 2) and the vertex A (different from the origin) is on the y axis, then the ordinate of A is:

A

2

B

$$\frac{7}{4}$$

C

$$\frac{7}{2}$$

D

$$\frac{5}{2}$$