Question 69

The perimeter of a rectangular table is 48 cm. If the area of the rectangular table is 128 $$cm^2$$, then what will be the length of the table?

Solution

Let length and breadth of the rectangle be $$l$$ cm and $$b$$ cm respectively.

Perimeter = $$2(l+b)=48$$

=> $$b=24-l$$ ---------------(i)

Area = $$lb=128$$ ----------(ii)

Substituting value of $$b$$ in equation (ii), we get :

=> $$l(24-l)=128$$

=> $$l^2-24l+128=0$$

=> $$(l-16)(l-8)=0$$

=> $$l=16,8$$

$$\therefore$$ Length = 16 cm and Breadth = 8 cm

=> Ans - (C)

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