Question 69

If x - y = 6 and xy = 40, then ﬁnd $$x^2 + y^2$$

Solution

Given : $$(x - y) = 6$$ and $$xy = 40$$

Using $$(x - y)^2 = x^2 + y^2 - 2xy$$

=> $$(6)^2 = (x^2 + y^2) - (2 \times 40)$$

=> $$(x^2 + y^2) = 36 + 80 = 116$$

=> Ans - (A)

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