Solution
Given : $$(x + y) = 10$$ and $$x^2 + y^2 = 68$$
Using $$(x + y)^2 = x^2 + y^2 + 2xy$$
=> $$(10)^2 = 68 + (2 \times xy)$$
=> $$2 xy = 100 - 68 = 32$$
=> $$xy = \frac{32}{2} = 16$$
=> Ans - (D)
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