Question 69

From a point, 40 m apart from the foot of a tower, the angle of elevation of its top is 60°. The height of the tower is

Solution

AB is the tower = $$h$$ = ?

In $$\triangle$$ ABC,

=> $$tan(60^\circ)=\frac{AB}{BC}$$

=> $$\sqrt{3}=\frac{h}{40}$$

=> $$h=40\sqrt{3}$$ m

=> Ans - (C)


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