Sign in
Please select an account to continue using cracku.in
↓ →
70% of the students who joined XCRI last year play football, 75% play cricket, 80% play basketball and 85% play carrom. The minimum percentage of students who play all four games is:
Let '100x' be the number of studentsΒ who joined XCRI last year.
Let 'a', 'b', 'c' and d be the number of students who play 1 game, 2 games, 3 games and 4 games respectively.Β
Therefore,Β
a+b+c+d = 100x ... (1)
a+2b+3c+4d = 70x+75x+80x+85x
a+2b+3c+4d = 310x ... (2)
By equation (2) - (1)
b+2c+3d = 210x ....(3)
To minimise d, we have to maximise c, as c has the highest coefficient in the above equation, and in order to maximise c, we need to minimise all a,b and d.Β
So let'sΒ put a=b=0 inorder to minimize a, b and dΒ Β in equations 1 and 3
c+d = 100x
2c+3d = 210x
Solving the above equations yields c = 90x and d = 10x.
Therefore, we can say that the minimum percentage of students who play all four games = 10%.
Click on the Email βοΈ to Watch the Video Solution
Create a FREE account and get:
Educational materials for CAT preparation