Question 69

129 meter from the foot of a cliff on level of ground, the angle of elevation of the top of a cliff is 30°. The height of this cliff is

Solution

Given : BC = 129 m and $$\angle$$ ACB = $$30^\circ$$

To find : AB is the cliff = ?

Solution : In $$\triangle$$ ABC,

=> $$tan(30^\circ)=\frac{AB}{BC}$$

=> $$\frac{1}{\sqrt{3}}=\frac{AB}{129}$$

=> $$AB=\frac{129}{\sqrt{3}}$$

=> $$AB = 43\sqrt3$$ m

=> Ans - (C)

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