PQRS is a parallelogram and M is any point with in it. If the area of the parallelogram PQRS is 40 Units, then what is the sum of the areas of the $$\triangle$$SMR and $$\triangle$$PMQ?

In the parallelogram PQRS, RX is the altitude on base PQ.
If we draw altitudes from M on SR and PQ, their sum will be equal to RX.
So, sum of areas of triangle PMQ and SMR = $$\left(\frac{1}{2}\times\ PQ\times\ H1\right)+\left(\frac{1}{2}\times SR\times\ H2\ \right)$$
PQ = SR, so it can be written as:
$$\frac{1}{2}\times\ PQ\times\left(\ H1+H2\right)$$
$$\frac{1}{2}\times\ PQ\times RX$$
$$PQ\times RX$$ = Area of parallelogram = 40 units.
So, sum of areas of triangles = $$\frac{1}{2}\times\ 40=20$$ units.