Solution
Given, $$2a+3b = 8$$ and $$ab = 5$$
$$=$$> $$\left(2a+3b\right)^2=8^2$$
$$=$$> $$4a^2+9b^2+2.2a.3b=64$$
$$=$$> $$4a^2+9b^2+12ab=64$$
$$=$$> $$4a^2+9b^2+12\left(5\right)=64$$
$$=$$> $$4a^2+9b^2=64-60$$
$$=$$> $$4a^2+9b^2=4$$
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