Solution
Given, $$2a+3b = 8$$ and $$ab = 5$$
$$=$$> $$\left(2a+3b\right)^2=8^2$$
$$=$$> $$4a^2+9b^2+2.2a.3b=64$$
$$=$$> $$4a^2+9b^2+12ab=64$$
$$=$$> $$4a^2+9b^2+12\left(5\right)=64$$
$$=$$> $$4a^2+9b^2=64-60$$
$$=$$> $$4a^2+9b^2=4$$
Get AI Help
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
