A spherical ball of diameter 35 cm rolls 20 times. How much is the distance (in m) covered by it?(Take $$\pi = \frac{22}{7}$$)
A spherical ball of diameter 35 cm.
the radius of spherical ball = r = $$\frac{35}{2}$$ cm
distance covered by spherical ball in one roll = $$2\pi\ r$$
= $$2\times\frac{22}{7}\times\ \frac{35}{2}\ $$
= $$22\times5\ $$
= 110 cm
distance covered by spherical ball in 20 roll = $$110\times20$$
= 2200 cm
= 22 m (1 m = 100 cm)
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