36 men and 48 women can do a certain work in one day whereas 6 men and 12 women can do it in 5 days. The number of women required to do the same work in 8 days is:

As we know, 

Total work = Efficiency $$\times\ $$ Time

Given, 

36 men and 48 women can do a certain work in one day whereas 6 men and 12 women can do it in 5 days. 

Therefore , 
(36m + 48w)$$\times\ $$1 = (6m+12w)$$\times\ $$5 

$$\therefore\ $$36m + 48w = 30m + 60w 

$$\therefore\ $$ 6m = 12w

$$\therefore\ \frac{m}{w}=\frac{2}{1}$$

total work = ((36$$\times\ $$2) + (48$$\times\ $$1))$$\times\ $$1

= 72 + 48 = 120 units

Number of womens required to complete the total work in 8 days = $$\frac{120}{8}=15$$

Hence, Option B is correct.