SSC CHSL 10 July 2019 Shift-2

Question 67

$$\theta$$ being an acute angle, it is given that $$\sec^2 \theta + 4 \tan^2 \theta = 6$$. What is the value of $$\theta$$ ?

Solution

$$\sec^2 \theta + 4 \tan^2 \theta = 6$$

$$(1+tan^2 \theta) + 4 \tan^2 \theta = 6$$

$$5 \tan^2 \theta = 5$$

$$\tan^2 \theta=1$$

$$\tan \theta=1$$

$$\tan\theta=45^\circ$$

$$\theta=45^\circ$$


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