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Question 67
$$\theta$$ being an acute angle, it is given that $$\sec^2 \theta + 4 \tan^2 \theta = 6$$. What is the value of $$\theta$$ ?
Solution
$$\sec^2 \theta + 4 \tan^2 \theta = 6$$
$$(1+tan^2 \theta) + 4 \tan^2 \theta = 6$$
$$5Â \tan^2 \theta = 5$$
$$\tan^2 \theta=1$$
$$\tan \theta=1$$
$$\tan\theta=45^\circ$$
$$\theta=45^\circ$$
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