Question 67

The side BC of the ΔABC is extended to the point D. If ∠ ACD = 112° and ∠B = 3/4 ∠A, then the value of ∠B is

Solution

Given : ∠ ACD = 112° and ∠B = 3/4 ∠A

Let $$\angle$$ A = $$4\theta$$

=> $$\angle$$ B = $$3\theta$$ = ?

Solution : Using exterior angle property

=> ∠A + ∠B = ∠ACD

=> $$4\theta+3\theta=112^\circ$$

=> $$7\theta=112^\circ$$

=> $$\theta=\frac{112}{7}=16^\circ$$

$$\therefore$$ $$\angle$$ B = $$3 \times 16=48^\circ$$

=> Ans - (B)

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