Solution
Given, $$a^2+\frac{2}{a^2}=16$$
$$\frac{72a^2}{a^4+2+8a^2}=\frac{72a^2}{a^2\left(a^2+\frac{2}{a^2}+8\right)}$$
$$=\frac{72}{a^2+\frac{2}{a^2}+8}$$
$$=\frac{72}{16+8}$$
$$=\frac{72}{24}$$
$$=3$$
Hence, the correct answer is Option D
Get AI Help
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
