Question 67

If $$1 - 64x^3 - 12x + px^2 = (1 - 4x)^3$$, then the value of p is:

Solution

$$1 - 64x^3 - 12x + px^2 = (1 - 4x)^3$$

$$1 - 64x^3 - 12x + px^2 = 1 - 64x^3 -12x + 48x^2$$

($$\because(a - b)^3 = a^3 - b^3 - 3a^2b + 3ab^2$$)

p = 48

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