Asum of ₹ 10000 is lent partly at 8% and remaining at 10% per annum.If the yearly interest on the average is 9.2%, then both parts are respectively.
Let the amount lent at 8% be Rs.x
Then, Amount lent at 10% will be Rs.(10000-x)
Time period = 1 year
$$\dfrac{x\times8}{100} + \dfrac{(10000-x)\times10}{100} = \dfrac{10000\times9.2}{100}$$
=> $$\dfrac{8x}{100}+\dfrac{100000-10x}{100} = 920$$
=> $$100000-2x = 92000$$
=> $$2x = 8000$$
=> $$x = 4000$$
Therefore, The amounts are Rs.4000 and Rs.6000.
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