Question 66

The length of a shadow of a vertical tower is $$ \frac{1}{\sqrt3} $$ times its height. The angle of elevation of the Sun is

Solution

let AB be the tower and BC be its shadow

assume AB = x

then $$ BC = \frac{x}{\sqrt3} $$

$$ tan \theta = \frac{AB}{BC} = x \times \frac{\sqrt 3}{x} = \sqrt 3 $$

$$ tan \theta = tan 60^\circ $$

$$ \theta = 60^\circ $$

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