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Question 66
The length, breadth and height of room is 16 metres, 12 metres and 15 metres. What will be the length of the largest rod that can be placed in that room?
Solution
The longest rod that can be placed in a room which is a cuboid is its diagonal.
Diagonal of the given cuboid = $$\sqrt{l^2 + b^2 + h^2} = \sqrt{16^2 + 12^2 + 15^2} = \sqrt{256+144+225} = \sqrt{625} = 25 m$$
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