Sign in
Please select an account to continue using cracku.in
↓ →
If $$9x^2+16y^2=60$$ and $$3x+4y=6$$, then the value of xy is
Given : $$9x^2+16y^2=60$$ ------------(i)
and $$3x+4y=6$$
Squaring both sides, we get :
=> $$(3x+4y)^2=(6)^2$$
=> $$9x^2+16y^2+2(3x)(4y)=36$$
=> $$60+24xy=36$$ [Using (i)]
=> $$24xy=36-60=-24$$
=> $$xy=\frac{-24}{24}=-1$$
=> Ans - (A)
Was this solution helpful?
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation