Question 66

A room is in the shape of cube and the length of the longest rod placed in it is $$21\sqrt3$$ cm. The area of the floor is:

Solution

A room is in the shape of cube and the length of the longest rod placed in it is $$21\sqrt3$$ cm.

Here the longest rod inside the cube is the diagonal of the room.

Diagonal of cube = $$\sqrt{3\ }\times\ side$$

$$21\sqrt3 = \sqrt{3\ }\times\ side$$

side = 21

Area of the floor = $$\left(side\right)^2$$

= $$\left(21\right)^2$$

= 441 $$cm^2$$

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