A copper wire is bent in the form of an equilateral triangle of area $$4 \sqrt{3} cm^2$$.If the same wire is bent into the form of a square, the area of the square will be:
Area of a equilateral triangle=$$\sqrt{3}a^{2}/4$$
$$\sqrt{3}a^{2}/4$$=$$4\sqrt{3}$$
a=4 cm
Total length =3*4
=12 cm
Side of each square=12/4
=3 cm
Area=9 sqcm
Create a FREE account and get:
Detailed syllabus & Topic-wise Weightage
By proceeding you agree to create your account
Free CAT Syllabus PDF will be sent to your email address soon !!!
