What is the total surface area (in sq cm) of a hollow cylinder open at both ends, if its length is 22 cm, external radius is 7 cm and thickness is 1 cm? (Take π = 22/7)

Let the external radius, the internal radius and the height of the hollow cylinder be R, r and h respectively.

=> R = 7 cm , h = 22 cm and r = 7 - 1 = 6 cm

Total surface area of hollow cylinder = $$(2 \pi R h) + (2 \pi r h) + 2 \pi(R^2 - r^2)$$

= $$(2 \times \frac{22}{7})[(7 \times 22) + (6 \times 22) + (7^2 - 6^2)]$$

= $$(\frac{44}{7}) \times (154 + 132 + 13)$$

= $$\frac{44}{7} \times 299 = 1879.428 \approx 1879.43$$ $$cm^2$$

=> Ans - (A)