The HCF of 56, 140 and 168 is:
Expressing the number as product of prime factors,
56 - 2$$^{3}$$ x 7
140 - 2$$^{2}$$ x 5 x 7
168 - 2$$^{3}$$ x 3 x 7
HCF is obtained by multiplying each common prime factor using the least power power of each prime factor.
Here common prime factors are 2, 7Â
Least power of 2 here is 2$$^{2}$$
Least power of 7 here is 7$$^{1}$$
HCF = 4x 7 = 28
Hence, option AÂ is the correct answer.
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