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Instructions
In each of the following questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.
Give answer If
a: x > y
b: x ≤ y
c: x ≥ y
d: x < y
e: Relationship between x and y cannot be established
Solution
I.$$x^{2} - 11x + 30 = 0$$
=> $$x^2 - 6x - 5x + 30 = 0$$
=> $$x (x - 6) - 5 (x - 6) = 0$$
=> $$(x - 6) (x - 5) = 0$$
=> $$x = 5 , 6$$
II.$$y^{2} - 15y + 56 = 0$$
=> $$y^2 - 8y - 7y + 56 = 0$$
=> $$y (y - 8) - 7 (y - 8) = 0$$
=> $$(y - 8) (y - 7) = 0$$
=> $$y = 7 , 8$$
Therefore $$x < y$$
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