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Instructions
In each of the following questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.
Give answer If
a: x > y
b: x ≤ y
c: x ≥ y
d: x < y
e: Relationship between x and y cannot be established
Solution
I.$$x^{2} + 11x + 28 = 0$$
=> $$x^2 + 7x + 4x + 28 = 0$$
=> $$x (x + 7) + 4 (x + 7) = 0$$
=> $$(x + 7) (x + 4) = 0$$
=> $$x = -7 , -4$$
II.$$5y^{2} + 27y + 28 = 0$$
=> $$5y^2 + 20y + 7y + 28 = 0$$
=> $$5y (y + 4) + 7 (y + 4) = 0$$
=> $$(y + 4) (5y + 7) = 0$$
=> $$y = -4 , \frac{-7}{5}$$
$$\therefore x \leq y$$
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