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$$x^y=y^x$$
We shift the power y from LHS to RHS
==> $$x\ =\ y^{\frac{x}{y}}$$.
No we substitute the value of $$y^{\frac{x}{y}}$$ in $$\left(\ \frac{x}{y}\right)^{\frac{x}{y}}$$, we get:
$$\frac{x^{\frac{x}{y}}}{x}=x^{\frac{x}{y}-1}$$.
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