Question 65

If the radius of the base of a right circular cylinder is 4 m and the area of the curved surface of the cylinder is 19.5 $$m^{2}$$, then its volume (in $$m^{3}$$) is:

Solution

Given,

Curved surface area (C.S.A) = 19.5 $$m^2$$

Radius (r) = 4 m

As we know,

$$C.S.A=\ 2\pi\ rh$$

$$h=\frac{19.5\times\ 7}{2\times\ 22\times\ 4}$$ = 0.775 m

Volume = $$\pi\ r^2h$$

= $$\frac{22}{7}\times\ 4\times\ 4\times\ .775\ \simeq\ 39\ m$$

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